Program to know whether a number is Magic Number or not.

Explanation :
If n=1729 then find the sum of digits of the given number i.e,
(1 + 7 + 2 + 9 =19). Reverse of 19 is 91.
Then (19 X 91 = 1729).
If the obtained product value and the given input are same, then the given number is a magic number.

Code:

import java.util.Scanner;
public class MagicNumber
{
    public static void main (String args[])
    {
        int num, sum, rev;
        Scanner sc=new Scanner(System.in);
        System.out.println("Enter the value for num:");
        num=sc.nextInt();
        MagicNumber m=new MagicNumber();
        sum = m.sumOfDigits(num);
        rev = m.reverse(sum);
        if (sum < 10)
        {
                if ((sum * sum) == num)
                {
                    System.out.println(num+" is a magic number");
                }
                else
                {
                    System.out.println(num+" is not a magic number");
                }
              
        }
        else if ((sum * rev) == num)
        {
            System.out.println(num+" is a magic number");
        }
        else
        {
            System.out.println(num+" is not a magic number");
        }
        sc.close();
    }
   
    public int sumOfDigits(int n)
    {
        int s = 0;
        while (n > 0)
        {
                s = s + (n % 10);
                n = n / 10;
        }
        return s;
    }

    public int reverse(int num)
    {
        int rev = 0;
        while (num > 0)
        {
                rev = (rev * 10) + (num % 10);
                num = num / 10;
        }
        return rev;
    }
}